5b^2=10b

Solution for 5b^2=10b equation:

5b^2=10b

We move all terms to the left:

5b^2-(10b)=0

a = 5; b = -10; c = 0;
Δ = b2-4ac
Δ = -102-4·5·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10}{2*5}=\frac{0}{10}
=0
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10}{2*5}=\frac{20}{10}
=2
$